Commonly method for power factor correction using the capacitor to generate reactive power ( kVAR ) to reduce apparent power ( kVA ) form inductive load.

This time i want share a simple method to sizing our capacitor to improve power factor for induction motor and utility electricity.This method also can use for capacitor bank sizing.

Power factor correction is the one of famous topic for all electrical person at around the world.Many discussion and debate about how to sizing the capacitor for power factor correction.

**How to sizing capacitor for power factor correction?**

To properly sizing the amount of capacitor (kVAR) required to correct the lagging power factor,we must have three (3) important of information below:

- kW (kilowatts)

- Existing Power Factor ( % )

- Desired Power Factor ( % )

From this information,now we can calculate the capacitor size for power factor correction.The formula to calculate the required kVAR is:

#### Factor from Table 1 below x kW = kVAR of capacitors required.

**Calculation Example :**

1 unit air-compressor ( 3 phase 415 VAC ) used an average of **90 kW** with an existing power factor of **80%**.The desired power factor is **95%**. The factor value for this case is 0.421 to raise the power factor from 80% to 95% using table 1.** **** **

0.421 x 90 kW = **38 kVAR**

So we need capacitor size 38 kVAR to get power factor 95% for 1 unit air-compressor 90 kW**.
**

If working power (kW) or Present Power Factor are not known you can calculate from the following formulas to get the three basic pieces of information required to calculate kVAR.The best range for desired power factor is around 95% until 100%.

If I had known this site earlier when she entered the Faculty of Electrical Engineering, read the threads started by Mr. Admin and I become a better engineer, thank you, Mr. Adam

Thanks for ur compliment

PLEASE HELP ME SIR I WANT FOURMALA CAPACITOR VOLTAGE & CURRENT

Are pf and efficiency of motors given nameplate of all motors?.

If no-load current is known(given in nameplate) can we estimate the size of capacitor required a) to start the motor (by reducing starting current)

b) to correct pf?.

We can estimate the full load ampere using the formula : – kW = ampere x Volt x 1.74

Hi

Nice explanation

There is something similar explained for capacitor sizing

hi pieface,thanks for share nice info :D

hello, nice article!!! I am really impressed. Actually this is my first time reading your post. But I am very fascinated by the way you explained this simple method in sizing up a to improve power factor for induction motor and utility electricity. Thanks for sharing this information. Really good. I will be subscribing to your feed. Rest assured that I will read your future posts..

HI stefanb2hv..thanks for ur compliment…are u supplier from germany?i like germany stuff.it have a high quality :D

dear sir,

thanks for reply

if i have a only motors HP ratting, then how i can know require KVA of capacitor??

thanking yoy

no problem bro,

do you mean for power factor correction for induction motor?

follow this step :-

1) Convert hp to kW;formula : 1 hp = 0.746 kW

2) from kW,you convert to Ampere;formula : I = kW / volt x 1.73

3) from ampere you can find the kVAR for power factor capacitor..for more detail please read my post about capacitor sizing for power factor.

I need no. of power factor capstor for 11 Kw motor

I need no. of power factor capstor for 11 Kw motor

My family members always say that I am killing my time here at web, except I know I

am getting experience all the time by reading such good articles.

dEAR SIR

There is panel with having a panel Incomer 800Amp now they want to install capacitor panel for same panel

How much Capacitor Kvar needed for the Panel

The method of calculation

There is panel with having a panel Incomer 2600Amp now they want to install capacitor panel for same panel

How much Capacitor Kvar needed for the Panel

Please calculate for me thank!

Dear sir,

I considered 65% diversity factor of connected load then what will be initial power factor.

e.g.

c.l. =275 kw

div =65%

TMD =178.7 kw